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Q1โ Section header โ
Q1โ Section header โ
1.1(2\
1.2(2\
1.3(2\
1.4(2\
1.5(2\
1.6(2\
1.7(2\
1.8(2\
1.9(2\
1.10(2\ [20] 1120
Q2โ Section header โ
Q2โ Section header โ
2.1Chemical bond is mutual attraction between two atoms resulting from the simultaneous attraction between their nuclei and outer electrons Chemiese binding is die wedersydse aantrekking tussen twee atome as
2.2.1(2\
2.2.2(2\
2.3
2.42,5 = 0,
2.5
2.6CN ha s a higher order bond/triple bond with more orbitals overlapping than CH, which is a single bond Thus CN bond nee ds more energy to
2.7CN has a longer bond length than CH because the H atom is smaller than the N atom CN het n grot er bindingslengte as CH omdat die
2.8Yes (1\
2.9HCN ha polar molecules with dipole dipole forces. O ha polar mole
Q3โ Section header โ
3.1has hydrogen bonds between the molecules has London forces/induced dipole forces has stronger intermolecular forces than N and therefor higher boiling point than N (Accept: more energy requires to overcome stronger
3.211
3.3both have weak London forces/induced dipole forces is a larger molecule /has a greater molecular mass /has a larger surface area than H therefore
3.4It has the weakest intermolecular forces /London forces It has t he low est boiling point It has the weakest intermolecular forces
Q4โ Section header โ
Q4โ Section header โ
4.1Boyle s law Boyle se wet (1\
4.2Criteria for hypothesis/ Riglyne vir hipotese The dependent and independent variables are stated correctly. Die afhanklike en onafhanklike veranderlikes korrek genoem. State the relationship between the dependent and independent
4.3Refer to the last page of the memo for the graph drawn to scale Verwys na die laaste bladsy van die memo vir die skaalgrafiek Criteria for marking the graph Nasienkriteria vir grafiek se of correct scale
4.4Any set of values can be used from the table Enige stel waardes vanaf die tabel kan gebruik word: 70(174\ = (300\V = 40, (Accept/ Aanvaar 40,32 40,8 dm
4.5At high pressure a gas starts to deviate from ideal gas behaviour because the volume of the molecules of a gas and the intermolecular forces start to influence the measured value, causing it to be greater than t
4.7Temperature is an indication of the average kinetic energy of the molecules of a gas. If the temperature of a gas decreases, the molecules move slower and closer together up to a point w ere the gas will start to
4.8pV = nRT (70 000\(174 x 10 = n(8, 31\( 293\ n = 5 moles [18
Q5โ Section header โ
Q5โ Section header โ
5.1n = 4 mole pV = nRT (120 000\V = (4\(8,31\(28 V = 0,
5.2POSITIVE
Q5โ Section header โ
Q5โ Section header โ
Q6โ Section header โ
Q6โ Section header โ
6.1.3Mark allocation/Nasienriglyne: Formula for/ Formule vir volume Substitution of 0,306 and 24,45 Vervanging van 0,306 en 24,45 Using ratio/ Gebruik verhouding
Q6โ Section header โ
Q6โ Section header โ
2.1Sulphuric acid Swawelsuur (1\ 10
6.2.2Mark allocation/ Punte toekenning Any one of the formulae/Enige een van formules Substitution of/ Vervanging van 3 g (5 g 2 g\ atio/ erhouding
Q7โ Section header โ
7.1he minimum energy needed for a reaction to take place. Die minimum energie benodig vir die reaksie om plaas te vind [2 or 0] (2\
7.2More e nergy is released than absorbed energy of products is less than energy of reactants H is negative Meer energie word afgegee as opgeneem OF energie van die produkte is minder as die energie van reaktante
7.3products reactants 183, 400 216, mol
7.4Criteria for marking/ Nasienkriteria Lower curved line Laer kurwelyn Lower activation energy indicated Laer ak tivering senergie aange
7.5One mole of any gas occupies the same volume at the same temperature and pressure. Een mol van enige gas beslaan dieselfde volume by dies lfde temperatuur en druk [2 or 0] (2\ Course of reaction
7.6OPTION 1/ OPSIE 1 4NH 4NO Initial vol Change in vol 7,5 Ratio Final vol
7.7= 1, 59 mol n(N\ 22,2 = 1, 5857 mol = 4, 625 mol H : N : O
Q8โ Section header โ
Q8โ Section header โ
8.1A hydroxide ion can act as proton acceptor n Hidroksiedioon kan optree as protonontvanger (2\
8.2Dative covalent bond Datiefkovalente binding (aq\ (aq\ (aq\ OR/ + NH (g\
8.6Mark allocation/Punte toekenning Usage of formula(e\ of c = n/V and/or n = m/M Usage or calculation of number of moles ( 3,75 mol of HNO atio erhouding 2:1
Q9โ Section header โ
Q9โ Section header โ
9.2Mn is +7 / Mn The oxidation number of S increases from 2 to 0 e oksidasiegetal van S neem toe
Q10โ Section header โ
10.1Danger ous for workers because they can be trapped underground. Sinkholes (Any relevant answer\ Gevaarlik vir werkers want hulle kan ondergronds vasgekeer
10.3Oxidati on number of O decreases from (in O to (in NaOH\ Die oksidasiegetal van O neem af van 0 (in O
10.5= 70 % (2\
10.6(Fe\ (0, 65\(2 500\ or/of (2 500\ = 1 625 Fe extracted ontgin (Accept/Aanvaar 1,625 x 10 (2\
4.3Graph of volume versus pressure/ Grafiek van volume teenoor druk Volume (dm Pressure/Druk (kPa\ 0 50 100 150 200 250 300